Yes pin 3 of the 2164 is the control voltage input. 0V and Iout mirrors Iin (the VCA is “wide open”), then for each increment of about 0.16V of this voltage, only half the current goes through. So you would effectively get a -0.16V / octave response (an inverting op-amp circuit can give you the proper 1V/octave response, you can copy Ripples’ schematics).
The cap is C5, C6 or C7 (as selected by the switch), and the buffer is U3B.
You need to replace this buffer by an inverting integrator built with U3B, so the topology changes a lot around U3B.
- C5 (or C6, C7) is no longer connected to ground or Z, but goes between pin 6 and 7 (feedback path).
- Pin 5 is only connected to BIAS.
- Pin 6 is connected to Z.
- R25 is still connected to pin 7.
- Pin 2 of the schmitt trigger (U3A) is only connected to pin 7 now.
And because this op-amp is now inverting, you need to swap all the Minus and Plus connection on the 4067 side.
A side effect of this change is that you’ll get a perfect triangle waveform. Good or bad?
Maybe at this point you can try drawing the schematics with all these changes!
But with all these changes in place, you can now insert a 2164: Vin to Z, Vout to pin 6 of the integrator.
At this point, I would guess it would make more sense to just throw that 4067 nonsense and replace it with a simple triangle VCO. Then a design a circuit that mixes an external CV with the NoteOn0 voltages, each with its own trimmer, and send it to that VCO. Adding voltage control to a circuit that can afford to be simple only because it doesn’t need voltage control is a much more complicated route than designing something voltage-controlled in the first place.